H=2t^2+4t+6

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Solution for H=2t^2+4t+6 equation: 



=2H^2+4H+6

We move all terms to the left:

-(2H^2+4H+6)=0

We get rid of parentheses

-2H^2-4H-6=0

a = -2; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·(-2)·(-6)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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